Minimum cost and list homomorphisms to semicomplete digraphs

• Authors: Gregory Gutin;Arash Rafiey;Anders Yeo
• Venue: Discrete Applied Mathematics
• Year: 2006

For digraphs D and H, a mapping f : V(D) → V(H) is a homomorphism of D to H if uv ∈ A(D) implies f(u) f(v) ∈ A(H). Let H be a fixed directed or undirected graph. The homomorphism problem for H asks whether a directed or undirected input graph D admits a homomorphism to H. The list homomorphism problem for H is a generalization of the homomorphism problem for H, where every vertex x ∈ V(D) is assigned a set Lx of possible colors (vertices of H).The following optimization version of these decision problems generalizes the list homomorphism problem and was introduced in Gutin et al. [Level of repair analysis and minimum cost homomorphisms of graphs, Discrete Appl. Math., to appear], where it was motivated by a real-world problem in defence logistics. Suppose we are given a pair of digraphs D, H and a positive integral cost ci(u) for each u ∈ V(D) and i ∈ V(H). The cost of a homomorphism f of D to H is Σu ∈ V(D) cf(u)(u). For a fixed digraph H, the minimum cost homomorphism problem for H is stated as follows: for an input digraph D and costs ci(u) for each u ∈ V(D) and i ∈ V(H), verify whether there is a homomorphism of D to H and, if one exists, find such a homomorphism of minimum cost.We obtain dichotomy classifications of the computational complexity of the list homomorphism and minimum cost homomorphism problems, when H is a semicomplete digraph (digraph in which there is at least one arc between any two vertices). Our dichotomy for the list homomorphism problem coincides with the one obtained by Bang-Jensen, Hell and MacGillivray in 1988 for the homomorphism problem when H is a semicomplete digraph: both problems are polynomial solvable if H has at most one cycle; otherwise, both problems are NP-complete. The dichotomy for the minimum cost homomorphism problem is different: the problem is polynomial time solvable if H is acyclic or H is a cycle of length 2 or 3; otherwise, the problem is NP-hard.